Friday, October 13, 2006

A challenging secondary school Geometry problem

Let ABC be an isoceles triagnel with equal angles 80 degress at B anc C. Cevians BD and CE divide angles at B and C into 60+20 and 30+50 degrees respectively. Find Angle EDB.

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1 Comments:

At 6:14 AM, Blogger debopam said...

the angle EDB is 0 degree.....and the two lines ED and BD will merge to each other.

 

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